Base | Representation |
---|---|
bin | 110001001001111101100000… |
… | …111111010010100110010011 |
3 | 1001100110110002121021212122001 |
4 | 301021331200333102212103 |
5 | 211314014133322020042 |
6 | 2043443433314254431 |
7 | 63352061102300212 |
oct | 6111754077224623 |
9 | 1040413077255561 |
10 | 216188806048147 |
11 | 62980180a90239 |
12 | 202b6a09887417 |
13 | 93826949215ba |
14 | 3b558460a7079 |
15 | 19ed8787dcbb7 |
hex | c49f60fd2993 |
216188806048147 has 2 divisors, whose sum is σ = 216188806048148. Its totient is φ = 216188806048146.
The previous prime is 216188806048133. The next prime is 216188806048153. The reversal of 216188806048147 is 741840608881612.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-216188806048147 is a prime.
It is not a weakly prime, because it can be changed into another prime (216188806048157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108094403024073 + 108094403024074.
It is an arithmetic number, because the mean of its divisors is an integer number (108094403024074).
Almost surely, 2216188806048147 is an apocalyptic number.
216188806048147 is a deficient number, since it is larger than the sum of its proper divisors (1).
216188806048147 is an equidigital number, since it uses as much as digits as its factorization.
216188806048147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 33030144, while the sum is 64.
The spelling of 216188806048147 in words is "two hundred sixteen trillion, one hundred eighty-eight billion, eight hundred six million, forty-eight thousand, one hundred forty-seven".
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