Base | Representation |
---|---|
bin | 11111011110001101111… |
… | …110101110010110100011 |
3 | 21122202102210202221120012 |
4 | 133132031332232112203 |
5 | 240413303122031011 |
6 | 4333315350435135 |
7 | 312152655416231 |
oct | 37361576562643 |
9 | 7582383687505 |
10 | 2162750580131 |
11 | 764243357569 |
12 | 2ab1a4962aab |
13 | 128c3c616bab |
14 | 7696b801951 |
15 | 3b3d1191a8b |
hex | 1f78dfae5a3 |
2162750580131 has 2 divisors, whose sum is σ = 2162750580132. Its totient is φ = 2162750580130.
The previous prime is 2162750580113. The next prime is 2162750580139. The reversal of 2162750580131 is 1310850572612.
It is a happy number.
Together with previous prime (2162750580113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2162750580131 - 210 = 2162750579107 is a prime.
It is a super-2 number, since 2×21627505801312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2162750580139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1081375290065 + 1081375290066.
It is an arithmetic number, because the mean of its divisors is an integer number (1081375290066).
Almost surely, 22162750580131 is an apocalyptic number.
2162750580131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2162750580131 is an equidigital number, since it uses as much as digits as its factorization.
2162750580131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100800, while the sum is 41.
The spelling of 2162750580131 in words is "two trillion, one hundred sixty-two billion, seven hundred fifty million, five hundred eighty thousand, one hundred thirty-one".
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