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2165354261141 is a prime number
BaseRepresentation
bin11111100000101001001…
…010111110101010010101
321200000011021001122110012
4133200221022332222111
5240434121142324031
64334430000410005
7312304332351041
oct37405112765225
97600137048405
102165354261141
1176535a036655
122ab7b0916905
13129265b78446
1476b37521021
153b4d4a4cb2b
hex1f8292bea95

2165354261141 has 2 divisors, whose sum is σ = 2165354261142. Its totient is φ = 2165354261140.

The previous prime is 2165354261101. The next prime is 2165354261197. The reversal of 2165354261141 is 1411624535612.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2099372064241 + 65982196900 = 1448921^2 + 256870^2 .

It is a cyclic number.

It is not a de Polignac number, because 2165354261141 - 222 = 2165350066837 is a prime.

It is a super-3 number, since 3×21653542611413 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2165354261101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1082677130570 + 1082677130571.

It is an arithmetic number, because the mean of its divisors is an integer number (1082677130571).

Almost surely, 22165354261141 is an apocalyptic number.

It is an amenable number.

2165354261141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2165354261141 is an equidigital number, since it uses as much as digits as its factorization.

2165354261141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 172800, while the sum is 41.

Adding to 2165354261141 its reverse (1411624535612), we get a palindrome (3576978796753).

The spelling of 2165354261141 in words is "two trillion, one hundred sixty-five billion, three hundred fifty-four million, two hundred sixty-one thousand, one hundred forty-one".