Base | Representation |
---|---|
bin | 1100100110101010001… |
… | …1101110001111010011 |
3 | 202200220202220022121221 |
4 | 3021222203232033103 |
5 | 12021431221123011 |
6 | 243250400225511 |
7 | 21433652413201 |
oct | 3115243561723 |
9 | 680822808557 |
10 | 216536114131 |
11 | 83917a9a527 |
12 | 35b7160b297 |
13 | 1755b1933ac |
14 | a6a232a071 |
15 | 5975068971 |
hex | 326a8ee3d3 |
216536114131 has 2 divisors, whose sum is σ = 216536114132. Its totient is φ = 216536114130.
The previous prime is 216536114101. The next prime is 216536114149. The reversal of 216536114131 is 131411635612.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 216536114131 - 211 = 216536112083 is a prime.
It is a super-3 number, since 3×2165361141313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (216536114101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108268057065 + 108268057066.
It is an arithmetic number, because the mean of its divisors is an integer number (108268057066).
Almost surely, 2216536114131 is an apocalyptic number.
216536114131 is a deficient number, since it is larger than the sum of its proper divisors (1).
216536114131 is an equidigital number, since it uses as much as digits as its factorization.
216536114131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12960, while the sum is 34.
Adding to 216536114131 its reverse (131411635612), we get a palindrome (347947749743).
The spelling of 216536114131 in words is "two hundred sixteen billion, five hundred thirty-six million, one hundred fourteen thousand, one hundred thirty-one".
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