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216670517053 is a prime number
BaseRepresentation
bin1100100111001010010…
…0011011011100111101
3202201021010210200202221
43021302210123130331
512022220123021203
6243312001045341
721440204002354
oct3116244333475
9681233720687
10216670517053
1183986949421
1235baa626851
131757cc90c53
14a6b611499b
155981c66abd
hex327291b73d

216670517053 has 2 divisors, whose sum is σ = 216670517054. Its totient is φ = 216670517052.

The previous prime is 216670516969. The next prime is 216670517101. The reversal of 216670517053 is 350715076612.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 214218088569 + 2452428484 = 462837^2 + 49522^2 .

It is a cyclic number.

It is not a de Polignac number, because 216670517053 - 233 = 208080582461 is a prime.

It is a super-4 number, since 4×2166705170534 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (216670517153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108335258526 + 108335258527.

It is an arithmetic number, because the mean of its divisors is an integer number (108335258527).

Almost surely, 2216670517053 is an apocalyptic number.

It is an amenable number.

216670517053 is a deficient number, since it is larger than the sum of its proper divisors (1).

216670517053 is an equidigital number, since it uses as much as digits as its factorization.

216670517053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 264600, while the sum is 43.

The spelling of 216670517053 in words is "two hundred sixteen billion, six hundred seventy million, five hundred seventeen thousand, fifty-three".