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21695312077861 is a prime number
BaseRepresentation
bin1001110111011010101010…
…10111101010010000100101
32211211001101121020012122211
410323231111113222100211
510320423444342442421
6114050404435323421
74366302025641652
oct473552527522045
984731347205584
1021695312077861
116a04a26088304
122524844150571
13c14b22726c86
145500b7142c29
15279528d459e1
hex13bb555ea425

21695312077861 has 2 divisors, whose sum is σ = 21695312077862. Its totient is φ = 21695312077860.

The previous prime is 21695312077763. The next prime is 21695312077871. The reversal of 21695312077861 is 16877021359612.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13382383341636 + 8312928736225 = 3658194^2 + 2883215^2 .

It is a cyclic number.

It is not a de Polignac number, because 21695312077861 - 29 = 21695312077349 is a prime.

It is a super-3 number, since 3×216953120778613 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21695312077796 and 21695312077805.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21695312077871) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10847656038930 + 10847656038931.

It is an arithmetic number, because the mean of its divisors is an integer number (10847656038931).

Almost surely, 221695312077861 is an apocalyptic number.

It is an amenable number.

21695312077861 is a deficient number, since it is larger than the sum of its proper divisors (1).

21695312077861 is an equidigital number, since it uses as much as digits as its factorization.

21695312077861 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7620480, while the sum is 58.

The spelling of 21695312077861 in words is "twenty-one trillion, six hundred ninety-five billion, three hundred twelve million, seventy-seven thousand, eight hundred sixty-one".