Base | Representation |
---|---|
bin | 11111100111001000000… |
… | …111111011011101100001 |
3 | 21200200010102210221101022 |
4 | 133213020013323131201 |
5 | 241042400344144431 |
6 | 4341540451015225 |
7 | 312642005251013 |
oct | 37471007733541 |
9 | 7620112727338 |
10 | 2172316006241 |
11 | 7683018317a7 |
12 | 2b101429a515 |
13 | 129b05278c44 |
14 | 771d7d601b3 |
15 | 3b790d0c07b |
hex | 1f9c81fb761 |
2172316006241 has 2 divisors, whose sum is σ = 2172316006242. Its totient is φ = 2172316006240.
The previous prime is 2172316006183. The next prime is 2172316006243. The reversal of 2172316006241 is 1426006132712.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2079897574225 + 92418432016 = 1442185^2 + 304004^2 .
It is a cyclic number.
It is not a de Polignac number, because 2172316006241 - 210 = 2172316005217 is a prime.
Together with 2172316006243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2172316006243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1086158003120 + 1086158003121.
It is an arithmetic number, because the mean of its divisors is an integer number (1086158003121).
Almost surely, 22172316006241 is an apocalyptic number.
It is an amenable number.
2172316006241 is a deficient number, since it is larger than the sum of its proper divisors (1).
2172316006241 is an equidigital number, since it uses as much as digits as its factorization.
2172316006241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 2172316006241 in words is "two trillion, one hundred seventy-two billion, three hundred sixteen million, six thousand, two hundred forty-one".
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