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22000220011331 is a prime number
BaseRepresentation
bin1010000000010010100110…
…10011000111101101000011
32212220012102011022002102122
411000021103103013231003
510340422422310330311
6114442432254434455
74430314650421262
oct500112323075503
985805364262378
1022000220011331
117012271719671
122573959202a2b
13c377c52baa13
14560b6001c5d9
152824223220db
hex1402534c7b43

22000220011331 has 2 divisors, whose sum is σ = 22000220011332. Its totient is φ = 22000220011330.

The previous prime is 22000220011309. The next prime is 22000220011333. The reversal of 22000220011331 is 13311002200022.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 22000220011331 - 214 = 22000219994947 is a prime.

It is a super-3 number, since 3×220002200113313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 22000220011333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (22000220011333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000110005665 + 11000110005666.

It is an arithmetic number, because the mean of its divisors is an integer number (11000110005666).

Almost surely, 222000220011331 is an apocalyptic number.

22000220011331 is a deficient number, since it is larger than the sum of its proper divisors (1).

22000220011331 is an equidigital number, since it uses as much as digits as its factorization.

22000220011331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 22000220011331 its reverse (13311002200022), we get a palindrome (35311222211353).

The spelling of 22000220011331 in words is "twenty-two trillion, two hundred twenty million, eleven thousand, three hundred thirty-one".