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2200104454433 is a prime number
BaseRepresentation
bin100000000001000000011…
…100011100100100100001
321210022212001200101000012
4200001000130130210201
5242021303220020213
64402414121534305
7314644432205654
oct40010034344441
97708761611005
102200104454433
11779071676166
122b648a644395
1312c6133c66b2
14786b27a189b
153c36a6d64a8
hex2004071c921

2200104454433 has 2 divisors, whose sum is σ = 2200104454434. Its totient is φ = 2200104454432.

The previous prime is 2200104454409. The next prime is 2200104454451. The reversal of 2200104454433 is 3344544010022.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1759092910864 + 441011543569 = 1326308^2 + 664087^2 .

It is a cyclic number.

It is not a de Polignac number, because 2200104454433 - 210 = 2200104453409 is a prime.

It is a super-2 number, since 2×22001044544332 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2200104454433.

It is not a weakly prime, because it can be changed into another prime (2200104454403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100052227216 + 1100052227217.

It is an arithmetic number, because the mean of its divisors is an integer number (1100052227217).

Almost surely, 22200104454433 is an apocalyptic number.

It is an amenable number.

2200104454433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2200104454433 is an equidigital number, since it uses as much as digits as its factorization.

2200104454433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 32.

Adding to 2200104454433 its reverse (3344544010022), we get a palindrome (5544648464455).

The spelling of 2200104454433 in words is "two trillion, two hundred billion, one hundred four million, four hundred fifty-four thousand, four hundred thirty-three".