Base | Representation |
---|---|
bin | 1010000000010100010011… |
… | …01010000101111100111011 |
3 | 2212220021202201101001222201 |
4 | 11000022021222011330323 |
5 | 10340431304243100011 |
6 | 114443102553531031 |
7 | 4430346363263431 |
oct | 500121152057473 |
9 | 85807681331881 |
10 | 22001132003131 |
11 | 701269a4a15a6 |
12 | 2573b72713a77 |
13 | c3790c222738 |
14 | 560c091bad51 |
15 | 28247741bcc1 |
hex | 140289a85f3b |
22001132003131 has 2 divisors, whose sum is σ = 22001132003132. Its totient is φ = 22001132003130.
The previous prime is 22001132003129. The next prime is 22001132003239. The reversal of 22001132003131 is 13130023110022.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22001132003131 - 21 = 22001132003129 is a prime.
It is a super-2 number, since 2×220011320031312 (a number of 27 digits) contains 22 as substring.
Together with 22001132003129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 22001132003099 and 22001132003108.
It is not a weakly prime, because it can be changed into another prime (22001132007131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000566001565 + 11000566001566.
It is an arithmetic number, because the mean of its divisors is an integer number (11000566001566).
Almost surely, 222001132003131 is an apocalyptic number.
22001132003131 is a deficient number, since it is larger than the sum of its proper divisors (1).
22001132003131 is an equidigital number, since it uses as much as digits as its factorization.
22001132003131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 22001132003131 its reverse (13130023110022), we get a palindrome (35131155113153).
The spelling of 22001132003131 in words is "twenty-two trillion, one billion, one hundred thirty-two million, three thousand, one hundred thirty-one".
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