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22001311310022 = 2321137281167081
BaseRepresentation
bin1010000000010100101000…
…10110000110000011000110
32212220022020012202210210200
411000022110112012003012
510340432141143410042
6114443132441031330
74430354001334152
oct500122426060306
985808205683720
1022001311310022
117012781730510
122574002785546
13c3793a412ca5
14560c24d34062
15282488039c4c
hex1402945860c6

22001311310022 has 72 divisors (see below), whose sum is σ = 53446575487032. Its totient is φ = 6486873033600.

The previous prime is 22001311309993. The next prime is 22001311310029.

22001311310022 is a `hidden beast` number, since 2 + 20 + 0 + 1 + 311 + 310 + 0 + 22 = 666.

22001311310022 is nontrivially palindromic in base 10.

It is a super-3 number, since 3×220013113100223 (a number of 41 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 22001311309977 and 22001311310004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (22001311310029) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 40312479 + ... + 40854602.

It is an arithmetic number, because the mean of its divisors is an integer number (742313548431).

Almost surely, 222001311310022 is an apocalyptic number.

22001311310022 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

22001311310022 is an abundant number, since it is smaller than the sum of its proper divisors (31445264177010).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

22001311310022 is a wasteful number, since it uses less digits than its factorization.

22001311310022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81167174 (or 81167134 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

It can be divided in two parts, 2200131 and 1310022, that added together give a palindrome (3510153).

The spelling of 22001311310022 in words is "twenty-two trillion, one billion, three hundred eleven million, three hundred ten thousand, twenty-two".

Divisors: 1 2 3 6 9 11 18 22 33 37 66 74 99 111 198 222 333 407 666 814 1221 1369 2442 2738 3663 4107 7326 8214 12321 15059 24642 30118 45177 90354 135531 271062 81167081 162334162 243501243 487002486 730503729 892837891 1461007458 1785675782 2678513673 3003181997 5357027346 6006363994 8035541019 9009545991 16071082038 18019091982 27028637973 33035001967 54057275946 66070003934 99105005901 111117733889 198210011802 222235467778 297315017703 333353201667 594630035406 666706403334 1000059605001 1222295072779 2000119210002 2444590145558 3666885218337 7333770436674 11000655655011 22001311310022