Search a number
-
+
220033130011127 is a prime number
BaseRepresentation
bin110010000001111001110100…
…100011011001100111110111
31001212001221222011001111200022
4302001321310203121213313
5212320010322240324002
62055545454030435355
764226604036646226
oct6201716443314767
91055057864044608
10220033130011127
1164122587704074
1220817a8a062b5b
1395a105c23caa4
143c49935c96cbd
151a68877724ba2
hexc81e748d99f7

220033130011127 has 2 divisors, whose sum is σ = 220033130011128. Its totient is φ = 220033130011126.

The previous prime is 220033130011091. The next prime is 220033130011139. The reversal of 220033130011127 is 721110031330022.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 220033130011127 - 216 = 220033129945591 is a prime.

It is a super-3 number, since 3×2200331300111273 (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 220033130011096 and 220033130011105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (220033130011027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110016565005563 + 110016565005564.

It is an arithmetic number, because the mean of its divisors is an integer number (110016565005564).

Almost surely, 2220033130011127 is an apocalyptic number.

220033130011127 is a deficient number, since it is larger than the sum of its proper divisors (1).

220033130011127 is an equidigital number, since it uses as much as digits as its factorization.

220033130011127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 220033130011127 its reverse (721110031330022), we get a palindrome (941143161341149).

The spelling of 220033130011127 in words is "two hundred twenty trillion, thirty-three billion, one hundred thirty million, eleven thousand, one hundred twenty-seven".