Base | Representation |
---|---|
bin | 110010000010000010001101… |
… | …110110001110100001101011 |
3 | 1001212002211020101001101222111 |
4 | 302002002031312032201223 |
5 | 212320132302420431103 |
6 | 2055553544322303151 |
7 | 64230343315150111 |
oct | 6202021566164153 |
9 | 1055084211041874 |
10 | 220042144311403 |
11 | 64126392a82307 |
12 | 20819784ab7ab7 |
13 | 95a1b6795908b |
14 | 3c4a14d151ab1 |
15 | 1a68c03cc886d |
hex | c8208dd8e86b |
220042144311403 has 2 divisors, whose sum is σ = 220042144311404. Its totient is φ = 220042144311402.
The previous prime is 220042144311391. The next prime is 220042144311413. The reversal of 220042144311403 is 304113441240022.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 220042144311403 - 25 = 220042144311371 is a prime.
It is not a weakly prime, because it can be changed into another prime (220042144311413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110021072155701 + 110021072155702.
It is an arithmetic number, because the mean of its divisors is an integer number (110021072155702).
Almost surely, 2220042144311403 is an apocalyptic number.
220042144311403 is a deficient number, since it is larger than the sum of its proper divisors (1).
220042144311403 is an equidigital number, since it uses as much as digits as its factorization.
220042144311403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 220042144311403 its reverse (304113441240022), we get a palindrome (524155585551425).
The spelling of 220042144311403 in words is "two hundred twenty trillion, forty-two billion, one hundred forty-four million, three hundred eleven thousand, four hundred three".
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