Base | Representation |
---|---|
bin | 1010000000100110111010… |
… | …00011100011001011101111 |
3 | 2212221020112212122210020112 |
4 | 11000103131003203023233 |
5 | 10341112234001314413 |
6 | 114451434111210235 |
7 | 4431152046340202 |
oct | 500233503431357 |
9 | 85836485583215 |
10 | 22011121119983 |
11 | 7016956052976 |
12 | 2575a9bb1697b |
13 | c3884189c378 |
14 | 5614b5b09939 |
15 | 28285e37a2a8 |
hex | 1404dd0e32ef |
22011121119983 has 2 divisors, whose sum is σ = 22011121119984. Its totient is φ = 22011121119982.
The previous prime is 22011121119941. The next prime is 22011121120057. The reversal of 22011121119983 is 38991112111022.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22011121119983 - 26 = 22011121119919 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 22011121119983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22011121113983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11005560559991 + 11005560559992.
It is an arithmetic number, because the mean of its divisors is an integer number (11005560559992).
Almost surely, 222011121119983 is an apocalyptic number.
22011121119983 is a deficient number, since it is larger than the sum of its proper divisors (1).
22011121119983 is an equidigital number, since it uses as much as digits as its factorization.
22011121119983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 41.
The spelling of 22011121119983 in words is "twenty-two trillion, eleven billion, one hundred twenty-one million, one hundred nineteen thousand, nine hundred eighty-three".
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