Base | Representation |
---|---|
bin | 1100110011111110110… |
… | …1000110100101001111 |
3 | 210001010222210020200001 |
4 | 3030333231012211033 |
5 | 12101242200321033 |
6 | 245041302345131 |
7 | 21621404102536 |
oct | 3147755064517 |
9 | 701128706601 |
10 | 220112120143 |
11 | 8539260a7a3 |
12 | 367ab12b1a7 |
13 | 179aacc2196 |
14 | a92123131d |
15 | 5ad3e8ae7d |
hex | 333fb4694f |
220112120143 has 2 divisors, whose sum is σ = 220112120144. Its totient is φ = 220112120142.
The previous prime is 220112120119. The next prime is 220112120147. The reversal of 220112120143 is 341021211022.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-220112120143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 220112120143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (220112120147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110056060071 + 110056060072.
It is an arithmetic number, because the mean of its divisors is an integer number (110056060072).
Almost surely, 2220112120143 is an apocalyptic number.
220112120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
220112120143 is an equidigital number, since it uses as much as digits as its factorization.
220112120143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 220112120143 its reverse (341021211022), we get a palindrome (561133331165).
The spelling of 220112120143 in words is "two hundred twenty billion, one hundred twelve million, one hundred twenty thousand, one hundred forty-three".
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