Base | Representation |
---|---|
bin | 1000001100110101… |
… | …1101100001010001 |
3 | 12200102012212101021 |
4 | 2003031131201101 |
5 | 14002021002311 |
6 | 1002234235441 |
7 | 105360054526 |
oct | 20315354121 |
9 | 5612185337 |
10 | 2201344081 |
11 | a2a668432 |
12 | 515285b81 |
13 | 2910b2381 |
14 | 16c50b14d |
15 | cd3d5171 |
hex | 8335d851 |
2201344081 has 2 divisors, whose sum is σ = 2201344082. Its totient is φ = 2201344080.
The previous prime is 2201344039. The next prime is 2201344097. The reversal of 2201344081 is 1804431022.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1157020225 + 1044323856 = 34015^2 + 32316^2 .
It is a cyclic number.
It is not a de Polignac number, because 2201344081 - 213 = 2201335889 is a prime.
It is a super-2 number, since 2×22013440812 = 9691831525907469122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2201344001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100672040 + 1100672041.
It is an arithmetic number, because the mean of its divisors is an integer number (1100672041).
Almost surely, 22201344081 is an apocalyptic number.
It is an amenable number.
2201344081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2201344081 is an equidigital number, since it uses as much as digits as its factorization.
2201344081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
The square root of 2201344081 is about 46918.4833621037. The cubic root of 2201344081 is about 1300.8562566052.
The spelling of 2201344081 in words is "two billion, two hundred one million, three hundred forty-four thousand, eighty-one".
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