Base | Representation |
---|---|
bin | 1010000000111011111101… |
… | …00101111100010010000011 |
3 | 2212222022201101202102200121 |
4 | 11000131332211330102003 |
5 | 10341303404311431201 |
6 | 114500543255201111 |
7 | 4432032061423654 |
oct | 500357645742203 |
9 | 85868641672617 |
10 | 22022421202051 |
11 | 7020724710876 |
12 | 2578114376197 |
13 | c39922a22c6a |
14 | 561c687b152b |
15 | 282cc14429a1 |
hex | 14077e97c483 |
22022421202051 has 2 divisors, whose sum is σ = 22022421202052. Its totient is φ = 22022421202050.
The previous prime is 22022421202043. The next prime is 22022421202057. The reversal of 22022421202051 is 15020212422022.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22022421202051 - 23 = 22022421202043 is a prime.
It is not a weakly prime, because it can be changed into another prime (22022421202057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11011210601025 + 11011210601026.
It is an arithmetic number, because the mean of its divisors is an integer number (11011210601026).
Almost surely, 222022421202051 is an apocalyptic number.
22022421202051 is a deficient number, since it is larger than the sum of its proper divisors (1).
22022421202051 is an equidigital number, since it uses as much as digits as its factorization.
22022421202051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 22022421202051 its reverse (15020212422022), we get a palindrome (37042633624073).
The spelling of 22022421202051 in words is "twenty-two trillion, twenty-two billion, four hundred twenty-one million, two hundred two thousand, fifty-one".
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