Base | Representation |
---|---|
bin | 1010000000111111101011… |
… | …11111111011011100001011 |
3 | 2212222111220000022200000221 |
4 | 11000133311333323130023 |
5 | 10341322010133044201 |
6 | 114501514141010511 |
7 | 4432132525254445 |
oct | 500376577733413 |
9 | 85874800280027 |
10 | 22024424503051 |
11 | 7021562502533 |
12 | 2578593253a37 |
13 | c39b81a84979 |
14 | 561db8889495 |
15 | 282d8c2584a1 |
hex | 1407f5ffb70b |
22024424503051 has 2 divisors, whose sum is σ = 22024424503052. Its totient is φ = 22024424503050.
The previous prime is 22024424503009. The next prime is 22024424503069. The reversal of 22024424503051 is 15030542442022.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22024424503051 - 29 = 22024424502539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22024424502998 and 22024424503016.
It is not a weakly prime, because it can be changed into another prime (22024424503351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11012212251525 + 11012212251526.
It is an arithmetic number, because the mean of its divisors is an integer number (11012212251526).
Almost surely, 222024424503051 is an apocalyptic number.
22024424503051 is a deficient number, since it is larger than the sum of its proper divisors (1).
22024424503051 is an equidigital number, since it uses as much as digits as its factorization.
22024424503051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 34.
Adding to 22024424503051 its reverse (15030542442022), we get a palindrome (37054966945073).
The spelling of 22024424503051 in words is "twenty-two trillion, twenty-four billion, four hundred twenty-four million, five hundred three thousand, fifty-one".
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