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22041412012033 is a prime number
BaseRepresentation
bin1010000001011111010101…
…00010001000100000000001
32220001010201220022112111021
411000233222202020200001
510342111302433341113
6114513403534145441
74433303510562631
oct500575242104001
986033656275437
1022041412012033
11702878a50a457
12257b934352281
13c3b65b2c372b
14562b4aa366c1
152835337b448d
hex140bea888801

22041412012033 has 2 divisors, whose sum is σ = 22041412012034. Its totient is φ = 22041412012032.

The previous prime is 22041412012003. The next prime is 22041412012049. The reversal of 22041412012033 is 33021021414022.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15174826758144 + 6866585253889 = 3895488^2 + 2620417^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-22041412012033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22041412011989 and 22041412012007.

It is not a weakly prime, because it can be changed into another prime (22041412012003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11020706006016 + 11020706006017.

It is an arithmetic number, because the mean of its divisors is an integer number (11020706006017).

Almost surely, 222041412012033 is an apocalyptic number.

It is an amenable number.

22041412012033 is a deficient number, since it is larger than the sum of its proper divisors (1).

22041412012033 is an equidigital number, since it uses as much as digits as its factorization.

22041412012033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 22041412012033 its reverse (33021021414022), we get a palindrome (55062433426055).

The spelling of 22041412012033 in words is "twenty-two trillion, forty-one billion, four hundred twelve million, twelve thousand, thirty-three".