Base | Representation |
---|---|
bin | 1010000001100011000101… |
… | …11001010000110010010011 |
3 | 2220001022221122001002100112 |
4 | 11000301202321100302103 |
5 | 10342124421410404303 |
6 | 114514340151311535 |
7 | 4433404530600656 |
oct | 500614271206223 |
9 | 86038848032315 |
10 | 22043431341203 |
11 | 7029626359338 |
12 | 25801b867b5ab |
13 | c3b8c0777a6c |
14 | 562c9ccc389d |
15 | 283600be40d8 |
hex | 140c62e50c93 |
22043431341203 has 2 divisors, whose sum is σ = 22043431341204. Its totient is φ = 22043431341202.
The previous prime is 22043431341163. The next prime is 22043431341221. The reversal of 22043431341203 is 30214313434022.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22043431341203 - 212 = 22043431337107 is a prime.
It is a super-4 number, since 4×220434313412034 (a number of 54 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 22043431341203.
It is not a weakly prime, because it can be changed into another prime (22043431341293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11021715670601 + 11021715670602.
It is an arithmetic number, because the mean of its divisors is an integer number (11021715670602).
Almost surely, 222043431341203 is an apocalyptic number.
22043431341203 is a deficient number, since it is larger than the sum of its proper divisors (1).
22043431341203 is an equidigital number, since it uses as much as digits as its factorization.
22043431341203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 22043431341203 its reverse (30214313434022), we get a palindrome (52257744775225).
The spelling of 22043431341203 in words is "twenty-two trillion, forty-three billion, four hundred thirty-one million, three hundred forty-one thousand, two hundred three".
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