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221002110113 is a prime number
BaseRepresentation
bin1100110111010011000…
…0001001010010100001
3210010110000110102101112
43031310300021102201
512110103020010423
6245305454113105
721652431640511
oct3156460112241
9703400412345
10221002110113
11857a9a253a4
12369b91ab795
1317ac04c2575
14a9a7503841
155b3718ba78
hex3374c094a1

221002110113 has 2 divisors, whose sum is σ = 221002110114. Its totient is φ = 221002110112.

The previous prime is 221002110079. The next prime is 221002110149. The reversal of 221002110113 is 311011200122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 190360307809 + 30641802304 = 436303^2 + 175048^2 .

It is a cyclic number.

It is not a de Polignac number, because 221002110113 - 216 = 221002044577 is a prime.

It is not a weakly prime, because it can be changed into another prime (221002110613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110501055056 + 110501055057.

It is an arithmetic number, because the mean of its divisors is an integer number (110501055057).

Almost surely, 2221002110113 is an apocalyptic number.

It is an amenable number.

221002110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

221002110113 is an equidigital number, since it uses as much as digits as its factorization.

221002110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 221002110113 its reverse (311011200122), we get a palindrome (532013310235).

Subtracting 221002110113 from its reverse (311011200122), we obtain a palindrome (90009090009).

The spelling of 221002110113 in words is "two hundred twenty-one billion, two million, one hundred ten thousand, one hundred thirteen".