Base | Representation |
---|---|
bin | 1100110111010011000… |
… | …0001001010010100001 |
3 | 210010110000110102101112 |
4 | 3031310300021102201 |
5 | 12110103020010423 |
6 | 245305454113105 |
7 | 21652431640511 |
oct | 3156460112241 |
9 | 703400412345 |
10 | 221002110113 |
11 | 857a9a253a4 |
12 | 369b91ab795 |
13 | 17ac04c2575 |
14 | a9a7503841 |
15 | 5b3718ba78 |
hex | 3374c094a1 |
221002110113 has 2 divisors, whose sum is σ = 221002110114. Its totient is φ = 221002110112.
The previous prime is 221002110079. The next prime is 221002110149. The reversal of 221002110113 is 311011200122.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 190360307809 + 30641802304 = 436303^2 + 175048^2 .
It is a cyclic number.
It is not a de Polignac number, because 221002110113 - 216 = 221002044577 is a prime.
It is not a weakly prime, because it can be changed into another prime (221002110613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110501055056 + 110501055057.
It is an arithmetic number, because the mean of its divisors is an integer number (110501055057).
Almost surely, 2221002110113 is an apocalyptic number.
It is an amenable number.
221002110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
221002110113 is an equidigital number, since it uses as much as digits as its factorization.
221002110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 221002110113 its reverse (311011200122), we get a palindrome (532013310235).
Subtracting 221002110113 from its reverse (311011200122), we obtain a palindrome (90009090009).
The spelling of 221002110113 in words is "two hundred twenty-one billion, two million, one hundred ten thousand, one hundred thirteen".
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