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2210031022013 is a prime number
BaseRepresentation
bin100000001010010000000…
…111010010111110111101
321211021110212021020210022
4200022100013102332331
5242202120420201023
64411135122421525
7315445425510143
oct40122007227675
97737425236708
102210031022013
117822a5995321
122b839ab018a5
13130535b12c19
1478d74c8b593
153c74bddb7c8
hex202901d2fbd

2210031022013 has 2 divisors, whose sum is σ = 2210031022014. Its totient is φ = 2210031022012.

The previous prime is 2210031021829. The next prime is 2210031022049. The reversal of 2210031022013 is 3102201300122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1199929640569 + 1010101381444 = 1095413^2 + 1005038^2 .

It is a cyclic number.

It is not a de Polignac number, because 2210031022013 - 212 = 2210031017917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2210031021982 and 2210031022000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2210031022063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105015511006 + 1105015511007.

It is an arithmetic number, because the mean of its divisors is an integer number (1105015511007).

Almost surely, 22210031022013 is an apocalyptic number.

It is an amenable number.

2210031022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2210031022013 is an equidigital number, since it uses as much as digits as its factorization.

2210031022013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2210031022013 its reverse (3102201300122), we get a palindrome (5312232322135).

The spelling of 2210031022013 in words is "two trillion, two hundred ten billion, thirty-one million, twenty-two thousand, thirteen".