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22102131224333 is a prime number
BaseRepresentation
bin1010000011010000011011…
…01011100010111100001101
32220020221110112020010001002
411001220031223202330031
510344110131043134313
6115001325013430045
74440553262430326
oct501501553427415
986227415203032
1022102131224333
117051508969346
12258b65b03b325
13c442b6a58a14
14565a6ac2544d
15284dd9232058
hex141a0dae2f0d

22102131224333 has 2 divisors, whose sum is σ = 22102131224334. Its totient is φ = 22102131224332.

The previous prime is 22102131224323. The next prime is 22102131224351. The reversal of 22102131224333 is 33342213120122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21340731877609 + 761399346724 = 4619603^2 + 872582^2 .

It is a cyclic number.

It is not a de Polignac number, because 22102131224333 - 220 = 22102130175757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22102131224296 and 22102131224305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22102131224323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11051065612166 + 11051065612167.

It is an arithmetic number, because the mean of its divisors is an integer number (11051065612167).

Almost surely, 222102131224333 is an apocalyptic number.

It is an amenable number.

22102131224333 is a deficient number, since it is larger than the sum of its proper divisors (1).

22102131224333 is an equidigital number, since it uses as much as digits as its factorization.

22102131224333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 22102131224333 its reverse (33342213120122), we get a palindrome (55444344344455).

The spelling of 22102131224333 in words is "twenty-two trillion, one hundred two billion, one hundred thirty-one million, two hundred twenty-four thousand, three hundred thirty-three".