Base | Representation |
---|---|
bin | 100000001011001010000… |
… | …011101000110000001101 |
3 | 21211100222121111000112011 |
4 | 200023022003220300031 |
5 | 242211113301004013 |
6 | 4411415410341221 |
7 | 315511501416523 |
oct | 40131203506015 |
9 | 7740877430464 |
10 | 2211003141133 |
11 | 7827546a5856 |
12 | 2b861058a811 |
13 | 13065c33a837 |
14 | 7902801c313 |
15 | 3c7a7411c3d |
hex | 202ca0e8c0d |
2211003141133 has 2 divisors, whose sum is σ = 2211003141134. Its totient is φ = 2211003141132.
The previous prime is 2211003141097. The next prime is 2211003141209. The reversal of 2211003141133 is 3311413001122.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1675064943049 + 535938198084 = 1294243^2 + 732078^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2211003141133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2211093141133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105501570566 + 1105501570567.
It is an arithmetic number, because the mean of its divisors is an integer number (1105501570567).
Almost surely, 22211003141133 is an apocalyptic number.
It is an amenable number.
2211003141133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2211003141133 is an equidigital number, since it uses as much as digits as its factorization.
2211003141133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 2211003141133 its reverse (3311413001122), we get a palindrome (5522416142255).
The spelling of 2211003141133 in words is "two trillion, two hundred eleven billion, three million, one hundred forty-one thousand, one hundred thirty-three".
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