Base | Representation |
---|---|
bin | 100000001011010000100… |
… | …111111010001101101011 |
3 | 21211101021021210100002112 |
4 | 200023100213322031223 |
5 | 242211330002010011 |
6 | 4411434343552535 |
7 | 315514310025632 |
oct | 40132047721553 |
9 | 7741237710075 |
10 | 2211113313131 |
11 | 782800904698 |
12 | 2b864145b74b |
13 | 130679103278 |
14 | 790388da519 |
15 | 3c7b1e2558b |
hex | 202d09fa36b |
2211113313131 has 2 divisors, whose sum is σ = 2211113313132. Its totient is φ = 2211113313130.
The previous prime is 2211113313109. The next prime is 2211113313133. The reversal of 2211113313131 is 1313133111122.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2211113313131 is a prime.
It is a super-2 number, since 2×22111133131312 (a number of 25 digits) contains 22 as substring.
Together with 2211113313133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2211113313097 and 2211113313106.
It is not a weakly prime, because it can be changed into another prime (2211113313133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105556656565 + 1105556656566.
It is an arithmetic number, because the mean of its divisors is an integer number (1105556656566).
Almost surely, 22211113313131 is an apocalyptic number.
2211113313131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2211113313131 is an equidigital number, since it uses as much as digits as its factorization.
2211113313131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 324, while the sum is 23.
Adding to 2211113313131 its reverse (1313133111122), we get a palindrome (3524246424253).
The spelling of 2211113313131 in words is "two trillion, two hundred eleven billion, one hundred thirteen million, three hundred thirteen thousand, one hundred thirty-one".
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