2211130054013 has 2 divisors, whose sum is σ = 2211130054014. Its totient is φ = 2211130054012.

The previous prime is 2211130053961. The next prime is 2211130054069. The reversal of 2211130054013 is 3104500311122.

2211130054013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1371271446169 + 839858607844 = 1171013^2 + 916438^2 .

It is a cyclic number.

It is not a de Polignac number, because 2211130054013 - 2³² = 2206835086717 is a prime.

It is a super-2 number, since 2×2211130054013² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2211130054013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2211130054213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105565027006 + 1105565027007.

It is an arithmetic number, because the mean of its divisors is an integer number (1105565027007).

Almost surely, 2^{2211130054013} is an apocalyptic number.

It is an amenable number.

2211130054013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2211130054013 is an equidigital number, since it uses as much as digits as its factorization.

2211130054013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 2211130054013 its reverse (3104500311122), we get a palindrome (5315630365135).

The spelling of 2211130054013 in words is "two trillion, two hundred eleven billion, one hundred thirty million, fifty-four thousand, thirteen".