Base | Representation |
---|---|
bin | 100000001011010110011… |
… | …001001010110010010011 |
3 | 21211101112000221020101021 |
4 | 200023112121022302103 |
5 | 242212024242042042 |
6 | 4411452122420311 |
7 | 315516563556541 |
oct | 40132631126223 |
9 | 7741460836337 |
10 | 2211210112147 |
11 | 78285050a183 |
12 | 2b8669961697 |
13 | 130693195aaa |
14 | 790476d6d91 |
15 | 3c7ba696867 |
hex | 202d664ac93 |
2211210112147 has 2 divisors, whose sum is σ = 2211210112148. Its totient is φ = 2211210112146.
The previous prime is 2211210112103. The next prime is 2211210112151. The reversal of 2211210112147 is 7412110121122.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2211210112147 is a prime.
It is a super-2 number, since 2×22112101121472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2211210112847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105605056073 + 1105605056074.
It is an arithmetic number, because the mean of its divisors is an integer number (1105605056074).
Almost surely, 22211210112147 is an apocalyptic number.
2211210112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2211210112147 is an equidigital number, since it uses as much as digits as its factorization.
2211210112147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 2211210112147 its reverse (7412110121122), we get a palindrome (9623320233269).
The spelling of 2211210112147 in words is "two trillion, two hundred eleven billion, two hundred ten million, one hundred twelve thousand, one hundred forty-seven".
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