Base | Representation |
---|---|
bin | 10100100110000010… |
… | …111010101010001001 |
3 | 2010002002202122211221 |
4 | 110212002322222021 |
5 | 330241430311431 |
6 | 14054133122041 |
7 | 1411661356021 |
oct | 244602725211 |
9 | 63062678757 |
10 | 22113135241 |
11 | 941831988a |
12 | 4351789321 |
13 | 2115414412 |
14 | 10dabd0a81 |
15 | 89652a111 |
hex | 5260baa89 |
22113135241 has 2 divisors, whose sum is σ = 22113135242. Its totient is φ = 22113135240.
The previous prime is 22113135227. The next prime is 22113135257. The reversal of 22113135241 is 14253131122.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18043205625 + 4069929616 = 134325^2 + 63796^2 .
It is a cyclic number.
It is not a de Polignac number, because 22113135241 - 219 = 22112610953 is a prime.
It is a super-3 number, since 3×221131352413 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (22113135841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11056567620 + 11056567621.
It is an arithmetic number, because the mean of its divisors is an integer number (11056567621).
Almost surely, 222113135241 is an apocalyptic number.
It is an amenable number.
22113135241 is a deficient number, since it is larger than the sum of its proper divisors (1).
22113135241 is an equidigital number, since it uses as much as digits as its factorization.
22113135241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
Adding to 22113135241 its reverse (14253131122), we get a palindrome (36366266363).
The spelling of 22113135241 in words is "twenty-two billion, one hundred thirteen million, one hundred thirty-five thousand, two hundred forty-one".
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