Base | Representation |
---|---|
bin | 1010000011100101000100… |
… | …00101100010100100001111 |
3 | 2220022000001200210002102200 |
4 | 11001302202011202210033 |
5 | 10344300324004013403 |
6 | 115010400251452543 |
7 | 4441424661116445 |
oct | 501624205424417 |
9 | 86260050702380 |
10 | 22113211001103 |
11 | 7056184135652 |
12 | 2591831757153 |
13 | c45361365c51 |
14 | 5663dc540b95 |
15 | 285336ccdca3 |
hex | 141ca216290f |
22113211001103 has 48 divisors (see below), whose sum is σ = 32973314486112. Its totient is φ = 14271409152000.
The previous prime is 22113211001093. The next prime is 22113211001117. The reversal of 22113211001103 is 30110011231122.
22113211001103 is a `hidden beast` number, since 221 + 1 + 321 + 10 + 0 + 110 + 3 = 666.
It is not a de Polignac number, because 22113211001103 - 25 = 22113211001071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (22113211001003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 805362351 + ... + 805389807.
It is an arithmetic number, because the mean of its divisors is an integer number (686944051794).
Almost surely, 222113211001103 is an apocalyptic number.
22113211001103 is a deficient number, since it is larger than the sum of its proper divisors (10860103485009).
22113211001103 is a wasteful number, since it uses less digits than its factorization.
22113211001103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44296 (or 44293 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 22113211001103 its reverse (30110011231122), we get a palindrome (52223222232225).
The spelling of 22113211001103 in words is "twenty-two trillion, one hundred thirteen billion, two hundred eleven million, one thousand, one hundred three".
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