Base | Representation |
---|---|
bin | 110010010011000011000001… |
… | …000011000100110110000011 |
3 | 1002000020120212021100110011202 |
4 | 302103003001003010312003 |
5 | 212443311102003002042 |
6 | 2102251012124531415 |
7 | 64410661415140004 |
oct | 6223030103046603 |
9 | 1060216767313152 |
10 | 221211234422147 |
11 | 64537180959082 |
12 | 209882769b0b6b |
13 | 965818c501c88 |
14 | 3c8a97645d1ab |
15 | 1a8932a058632 |
hex | c930c10c4d83 |
221211234422147 has 2 divisors, whose sum is σ = 221211234422148. Its totient is φ = 221211234422146.
The previous prime is 221211234422119. The next prime is 221211234422237. The reversal of 221211234422147 is 741224432112122.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 221211234422147 - 216 = 221211234356611 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 221211234422147.
It is not a weakly prime, because it can be changed into another prime (221211234472147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110605617211073 + 110605617211074.
It is an arithmetic number, because the mean of its divisors is an integer number (110605617211074).
Almost surely, 2221211234422147 is an apocalyptic number.
221211234422147 is a deficient number, since it is larger than the sum of its proper divisors (1).
221211234422147 is an equidigital number, since it uses as much as digits as its factorization.
221211234422147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86016, while the sum is 38.
Adding to 221211234422147 its reverse (741224432112122), we get a palindrome (962435666534269).
The spelling of 221211234422147 in words is "two hundred twenty-one trillion, two hundred eleven billion, two hundred thirty-four million, four hundred twenty-two thousand, one hundred forty-seven".
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