Base | Representation |
---|---|
bin | 1100111000001100101… |
… | …1010100010101111111 |
3 | 210011001212211111201200 |
4 | 3032003023110111333 |
5 | 12111101443124203 |
6 | 245345501110543 |
7 | 21661430641212 |
oct | 3160313242577 |
9 | 704055744650 |
10 | 221244114303 |
11 | 85913597763 |
12 | 36a66258453 |
13 | 17b2b695704 |
14 | a9cb6db779 |
15 | 5b4d5419a3 |
hex | 33832d457f |
221244114303 has 48 divisors (see below), whose sum is σ = 336284282880. Its totient is φ = 139971499200.
The previous prime is 221244114283. The next prime is 221244114341. The reversal of 221244114303 is 303411442122.
221244114303 is a `hidden beast` number, since 2 + 2 + 1 + 244 + 114 + 303 = 666.
It is not a de Polignac number, because 221244114303 - 233 = 212654179711 is a prime.
It is a super-2 number, since 2×2212441143032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (221244110303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 48188538 + ... + 48193128.
It is an arithmetic number, because the mean of its divisors is an integer number (7005922560).
Almost surely, 2221244114303 is an apocalyptic number.
221244114303 is a deficient number, since it is larger than the sum of its proper divisors (115040168577).
221244114303 is a wasteful number, since it uses less digits than its factorization.
221244114303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7940 (or 7937 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 221244114303 its reverse (303411442122), we get a palindrome (524655556425).
The spelling of 221244114303 in words is "two hundred twenty-one billion, two hundred forty-four million, one hundred fourteen thousand, three hundred three".
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