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22130250433 is a prime number
BaseRepresentation
bin10100100111000100…
…001101001011000001
32010010021222012110221
4110213010031023001
5330310321003213
614055544023041
71412260011364
oct244704151301
963107865427
1022130250433
119426a49775
124357461a81
132118b27755
1410dd1a80db
15897cab38d
hex52710d2c1

22130250433 has 2 divisors, whose sum is σ = 22130250434. Its totient is φ = 22130250432.

The previous prime is 22130250421. The next prime is 22130250473. The reversal of 22130250433 is 33405203122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11179255824 + 10950994609 = 105732^2 + 104647^2 .

It is a cyclic number.

It is not a de Polignac number, because 22130250433 - 225 = 22096696001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22130250398 and 22130250407.

It is not a weakly prime, because it can be changed into another prime (22130250473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11065125216 + 11065125217.

It is an arithmetic number, because the mean of its divisors is an integer number (11065125217).

Almost surely, 222130250433 is an apocalyptic number.

It is an amenable number.

22130250433 is a deficient number, since it is larger than the sum of its proper divisors (1).

22130250433 is an equidigital number, since it uses as much as digits as its factorization.

22130250433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 22130250433 its reverse (33405203122), we get a palindrome (55535453555).

The spelling of 22130250433 in words is "twenty-two billion, one hundred thirty million, two hundred fifty thousand, four hundred thirty-three".