Base | Representation |
---|---|
bin | 100000001101010011101… |
… | …100000010100010110111 |
3 | 21211120221112101221002001 |
4 | 200031103230002202313 |
5 | 242230330411224002 |
6 | 4412440454000131 |
7 | 315622640245153 |
oct | 40152354024267 |
9 | 7746845357061 |
10 | 2213312211127 |
11 | 78372a051266 |
12 | 2b8b55946047 |
13 | 13093983a144 |
14 | 791a696c063 |
15 | 3c88eec5a87 |
hex | 20353b028b7 |
2213312211127 has 2 divisors, whose sum is σ = 2213312211128. Its totient is φ = 2213312211126.
The previous prime is 2213312211109. The next prime is 2213312211161. The reversal of 2213312211127 is 7211122133122.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2213312211127 - 211 = 2213312209079 is a prime.
It is a super-2 number, since 2×22133122111272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2213312211095 and 2213312211104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2213312211527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106656105563 + 1106656105564.
It is an arithmetic number, because the mean of its divisors is an integer number (1106656105564).
Almost surely, 22213312211127 is an apocalyptic number.
2213312211127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2213312211127 is an equidigital number, since it uses as much as digits as its factorization.
2213312211127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2016, while the sum is 28.
Adding to 2213312211127 its reverse (7211122133122), we get a palindrome (9424434344249).
The spelling of 2213312211127 in words is "two trillion, two hundred thirteen billion, three hundred twelve million, two hundred eleven thousand, one hundred twenty-seven".
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