Base | Representation |
---|---|
bin | 100000001101111110000… |
… | …101110100101111111001 |
3 | 21211122210010000220120121 |
4 | 200031332011310233321 |
5 | 242233310021112213 |
6 | 4413035225453241 |
7 | 315646366126312 |
oct | 40157605645771 |
9 | 7748703026517 |
10 | 2214023613433 |
11 | 783a64679355 |
12 | 2b9114041221 |
13 | 130a2103c458 |
14 | 79233233609 |
15 | 3c8d269b88d |
hex | 2037e174bf9 |
2214023613433 has 2 divisors, whose sum is σ = 2214023613434. Its totient is φ = 2214023613432.
The previous prime is 2214023613379. The next prime is 2214023613491. The reversal of 2214023613433 is 3343163204122.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2189207282409 + 24816331024 = 1479597^2 + 157532^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2214023613433 is a prime.
It is not a weakly prime, because it can be changed into another prime (2211023613433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1107011806716 + 1107011806717.
It is an arithmetic number, because the mean of its divisors is an integer number (1107011806717).
Almost surely, 22214023613433 is an apocalyptic number.
It is an amenable number.
2214023613433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2214023613433 is an equidigital number, since it uses as much as digits as its factorization.
2214023613433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 2214023613433 its reverse (3343163204122), we get a palindrome (5557186817555).
The spelling of 2214023613433 in words is "two trillion, two hundred fourteen billion, twenty-three million, six hundred thirteen thousand, four hundred thirty-three".
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