Base | Representation |
---|---|
bin | 1010000100011101001011… |
… | …11010100101101010010011 |
3 | 2220101212211102211022220221 |
4 | 11002032211322211222103 |
5 | 10400244030020311011 |
6 | 115032302053013511 |
7 | 4443542415351064 |
oct | 502164572455223 |
9 | 86355742738827 |
10 | 22143340010131 |
11 | 7067a3518400a |
12 | 259763b924297 |
13 | c4815338a742 |
14 | 567a59b6c56b |
15 | 285eebddc971 |
hex | 1423a5ea5a93 |
22143340010131 has 2 divisors, whose sum is σ = 22143340010132. Its totient is φ = 22143340010130.
The previous prime is 22143340010089. The next prime is 22143340010147. The reversal of 22143340010131 is 13101004334122.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22143340010131 is a prime.
It is a super-2 number, since 2×221433400101312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 22143340010096 and 22143340010105.
It is not a weakly prime, because it can be changed into another prime (22143340010161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11071670005065 + 11071670005066.
It is an arithmetic number, because the mean of its divisors is an integer number (11071670005066).
Almost surely, 222143340010131 is an apocalyptic number.
22143340010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
22143340010131 is an equidigital number, since it uses as much as digits as its factorization.
22143340010131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 22143340010131 its reverse (13101004334122), we get a palindrome (35244344344253).
The spelling of 22143340010131 in words is "twenty-two trillion, one hundred forty-three billion, three hundred forty million, ten thousand, one hundred thirty-one".
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