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2214345134581 is a prime number
BaseRepresentation
bin100000001110010001010…
…000010101000111110101
321211200121112000212200021
4200032101100111013311
5242234434323301311
64413131153045141
7315660352041616
oct40162120250765
97750545025607
102214345134581
1178410a111a08
122b91a38567b1
13130a72833b58
1479263c09c0d
153c900a0c171
hex203914151f5

2214345134581 has 2 divisors, whose sum is σ = 2214345134582. Its totient is φ = 2214345134580.

The previous prime is 2214345134503. The next prime is 2214345134593. The reversal of 2214345134581 is 1854315434122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1140912378225 + 1073432756356 = 1068135^2 + 1036066^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2214345134581 is a prime.

It is a super-2 number, since 2×22143451345812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2214345134501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1107172567290 + 1107172567291.

It is an arithmetic number, because the mean of its divisors is an integer number (1107172567291).

Almost surely, 22214345134581 is an apocalyptic number.

It is an amenable number.

2214345134581 is a deficient number, since it is larger than the sum of its proper divisors (1).

2214345134581 is an equidigital number, since it uses as much as digits as its factorization.

2214345134581 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 460800, while the sum is 43.

The spelling of 2214345134581 in words is "two trillion, two hundred fourteen billion, three hundred forty-five million, one hundred thirty-four thousand, five hundred eighty-one".