Base | Representation |
---|---|
bin | 110010010110011010000011… |
… | …100101001001100110001111 |
3 | 1002001001122211212202021212002 |
4 | 302112122003211021212033 |
5 | 213011101441114313403 |
6 | 2102545035532302515 |
7 | 64433444310106604 |
oct | 6226320345114617 |
9 | 1061048755667762 |
10 | 221442131401103 |
11 | 64616098211928 |
12 | 20a04b75911a3b |
13 | 9673b98992802 |
14 | 3c97bdbb5a6ab |
15 | 1a90340c38188 |
hex | c9668394998f |
221442131401103 has 2 divisors, whose sum is σ = 221442131401104. Its totient is φ = 221442131401102.
The previous prime is 221442131401097. The next prime is 221442131401121. The reversal of 221442131401103 is 301104131244122.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 221442131401103 - 218 = 221442131138959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (221442131400103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110721065700551 + 110721065700552.
It is an arithmetic number, because the mean of its divisors is an integer number (110721065700552).
Almost surely, 2221442131401103 is an apocalyptic number.
221442131401103 is a deficient number, since it is larger than the sum of its proper divisors (1).
221442131401103 is an equidigital number, since it uses as much as digits as its factorization.
221442131401103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 221442131401103 its reverse (301104131244122), we get a palindrome (522546262645225).
The spelling of 221442131401103 in words is "two hundred twenty-one trillion, four hundred forty-two billion, one hundred thirty-one million, four hundred one thousand, one hundred three".
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