Base | Representation |
---|---|
bin | 100000001110010101111… |
… | …001110010110100110011 |
3 | 21211200210221202120222021 |
4 | 200032111321302310303 |
5 | 242240114304104021 |
6 | 4413143020252311 |
7 | 315662316615154 |
oct | 40162571626463 |
9 | 7750727676867 |
10 | 2214423113011 |
11 | 78414a13229a |
12 | 2b92059a1097 |
13 | 130a85a37035 |
14 | 7927030792b |
15 | 3c9077b1c41 |
hex | 20395e72d33 |
2214423113011 has 2 divisors, whose sum is σ = 2214423113012. Its totient is φ = 2214423113010.
The previous prime is 2214423112969. The next prime is 2214423113029. The reversal of 2214423113011 is 1103113244122.
2214423113011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2214423113011 - 227 = 2214288895283 is a prime.
It is a super-2 number, since 2×22144231130112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2214423153011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1107211556505 + 1107211556506.
It is an arithmetic number, because the mean of its divisors is an integer number (1107211556506).
Almost surely, 22214423113011 is an apocalyptic number.
2214423113011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2214423113011 is an equidigital number, since it uses as much as digits as its factorization.
2214423113011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2214423113011 its reverse (1103113244122), we get a palindrome (3317536357133).
The spelling of 2214423113011 in words is "two trillion, two hundred fourteen billion, four hundred twenty-three million, one hundred thirteen thousand, eleven".
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