Base | Representation |
---|---|
bin | 100000010100011101111… |
… | …111101101000110011111 |
3 | 21212022210101211200202101 |
4 | 200110131333231012133 |
5 | 242342102320043403 |
6 | 4420151450305531 |
7 | 316314324552442 |
oct | 40243577550637 |
9 | 7768711750671 |
10 | 2221001331103 |
11 | 786a15393975 |
12 | 2ba540a282a7 |
13 | 131593843189 |
14 | 796d5c2d659 |
15 | 3cb9006371d |
hex | 2051dfed19f |
2221001331103 has 2 divisors, whose sum is σ = 2221001331104. Its totient is φ = 2221001331102.
The previous prime is 2221001331079. The next prime is 2221001331149. The reversal of 2221001331103 is 3011331001222.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2221001331103 - 25 = 2221001331071 is a prime.
It is a super-2 number, since 2×22210013311032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2221001331173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110500665551 + 1110500665552.
It is an arithmetic number, because the mean of its divisors is an integer number (1110500665552).
Almost surely, 22221001331103 is an apocalyptic number.
2221001331103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2221001331103 is an equidigital number, since it uses as much as digits as its factorization.
2221001331103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2221001331103 its reverse (3011331001222), we get a palindrome (5232332332325).
It can be divided in two parts, 222100 and 1331103, that added together give a triangular number (1553203 = T1762).
The spelling of 2221001331103 in words is "two trillion, two hundred twenty-one billion, one million, three hundred thirty-one thousand, one hundred three".
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