Base | Representation |
---|---|
bin | 10100101011111100… |
… | …000110110001011011 |
3 | 2010022222211011211121 |
4 | 110223330012301123 |
5 | 330442233410042 |
6 | 14112024310111 |
7 | 1414301665552 |
oct | 245374066133 |
9 | 63288734747 |
10 | 22212013147 |
11 | 9469114265 |
12 | 437a912337 |
13 | 212ca5425c |
14 | 1109dacd99 |
15 | 8a005c367 |
hex | 52bf06c5b |
22212013147 has 2 divisors, whose sum is σ = 22212013148. Its totient is φ = 22212013146.
The previous prime is 22212013091. The next prime is 22212013151. The reversal of 22212013147 is 74131021222.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22212013147 is a prime.
It is not a weakly prime, because it can be changed into another prime (22212013847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11106006573 + 11106006574.
It is an arithmetic number, because the mean of its divisors is an integer number (11106006574).
Almost surely, 222212013147 is an apocalyptic number.
22212013147 is a deficient number, since it is larger than the sum of its proper divisors (1).
22212013147 is an equidigital number, since it uses as much as digits as its factorization.
22212013147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 22212013147 its reverse (74131021222), we get a palindrome (96343034369).
The spelling of 22212013147 in words is "twenty-two billion, two hundred twelve million, thirteen thousand, one hundred forty-seven".
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