Base | Representation |
---|---|
bin | 100000010100101010011… |
… | …011101101101011101111 |
3 | 21212100022221111011211011 |
4 | 200110222123231223233 |
5 | 242343014230000421 |
6 | 4420224303010051 |
7 | 316322440324054 |
oct | 40245233555357 |
9 | 7770287434734 |
10 | 2221210000111 |
11 | 787012157aa3 |
12 | 2ba59a899927 |
13 | 1315c7b4426b |
14 | 7971582b02b |
15 | 3cba35314e1 |
hex | 2052a6edaef |
2221210000111 has 2 divisors, whose sum is σ = 2221210000112. Its totient is φ = 2221210000110.
The previous prime is 2221210000069. The next prime is 2221210000117. The reversal of 2221210000111 is 1110000121222.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2221210000111 - 215 = 2221209967343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2221210000091 and 2221210000100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2221210000117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110605000055 + 1110605000056.
It is an arithmetic number, because the mean of its divisors is an integer number (1110605000056).
Almost surely, 22221210000111 is an apocalyptic number.
2221210000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2221210000111 is an equidigital number, since it uses as much as digits as its factorization.
2221210000111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2221210000111 its reverse (1110000121222), we get a palindrome (3331210121333).
The spelling of 2221210000111 in words is "two trillion, two hundred twenty-one billion, two hundred ten million, one hundred eleven", and thus it is an aban number.
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