Base | Representation |
---|---|
bin | 1010000110011110111100… |
… | …00110000010100101100111 |
3 | 2220122112122022011201221102 |
4 | 11003033132012002211213 |
5 | 10402414212003404111 |
6 | 115124302351310315 |
7 | 4451556616534334 |
oct | 503173606024547 |
9 | 86575568151842 |
10 | 22213002013031 |
11 | 70945325a9935 |
12 | 25a904151b39b |
13 | c518a57922bb |
14 | 56b18791d98b |
15 | 287c279d613b |
hex | 1433de182967 |
22213002013031 has 2 divisors, whose sum is σ = 22213002013032. Its totient is φ = 22213002013030.
The previous prime is 22213002013003. The next prime is 22213002013043. The reversal of 22213002013031 is 13031020031222.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22213002013031 is a prime.
It is a super-2 number, since 2×222130020130312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 22213002012994 and 22213002013012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22213002013331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11106501006515 + 11106501006516.
It is an arithmetic number, because the mean of its divisors is an integer number (11106501006516).
Almost surely, 222213002013031 is an apocalyptic number.
22213002013031 is a deficient number, since it is larger than the sum of its proper divisors (1).
22213002013031 is an equidigital number, since it uses as much as digits as its factorization.
22213002013031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 22213002013031 its reverse (13031020031222), we get a palindrome (35244022044253).
The spelling of 22213002013031 in words is "twenty-two trillion, two hundred thirteen billion, two million, thirteen thousand, thirty-one".
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