Base | Representation |
---|---|
bin | 100000010100110101111… |
… | …001101111111101001101 |
3 | 21212100211100120021120011 |
4 | 200110311321233331031 |
5 | 242343413010014432 |
6 | 4420255335153221 |
7 | 316330265023063 |
oct | 40246571577515 |
9 | 7770740507504 |
10 | 2221402423117 |
11 | 787100835279 |
12 | 2ba633215811 |
13 | 131628977827 |
14 | 797331da033 |
15 | 3cbb5390847 |
hex | 20535e6ff4d |
2221402423117 has 2 divisors, whose sum is σ = 2221402423118. Its totient is φ = 2221402423116.
The previous prime is 2221402423103. The next prime is 2221402423129. The reversal of 2221402423117 is 7113242041222.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2053887393321 + 167515029796 = 1433139^2 + 409286^2 .
It is a cyclic number.
It is not a de Polignac number, because 2221402423117 - 219 = 2221401898829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2221402423147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110701211558 + 1110701211559.
It is an arithmetic number, because the mean of its divisors is an integer number (1110701211559).
Almost surely, 22221402423117 is an apocalyptic number.
It is an amenable number.
2221402423117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2221402423117 is an equidigital number, since it uses as much as digits as its factorization.
2221402423117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 2221402423117 its reverse (7113242041222), we get a palindrome (9334644464339).
The spelling of 2221402423117 in words is "two trillion, two hundred twenty-one billion, four hundred two million, four hundred twenty-three thousand, one hundred seventeen".
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