Base | Representation |
---|---|
bin | 100000011101111001010… |
… | …111001000001000010011 |
3 | 21220021220212200021112212 |
4 | 200131321113020020103 |
5 | 243023320234213441 |
6 | 4424544141142335 |
7 | 320123223133541 |
oct | 40357127101023 |
9 | 7807825607485 |
10 | 2231124132371 |
11 | 79023a453332 |
12 | 3004a6b5a9ab |
13 | 132517ac8604 |
14 | 79db63dad91 |
15 | 3d083acbeeb |
hex | 207795c8213 |
2231124132371 has 2 divisors, whose sum is σ = 2231124132372. Its totient is φ = 2231124132370.
The previous prime is 2231124132359. The next prime is 2231124132397. The reversal of 2231124132371 is 1732314211322.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2231124132371 is a prime.
It is a super-3 number, since 3×22311241323713 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2231124132331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1115562066185 + 1115562066186.
It is an arithmetic number, because the mean of its divisors is an integer number (1115562066186).
Almost surely, 22231124132371 is an apocalyptic number.
2231124132371 is a deficient number, since it is larger than the sum of its proper divisors (1).
2231124132371 is an equidigital number, since it uses as much as digits as its factorization.
2231124132371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12096, while the sum is 32.
Adding to 2231124132371 its reverse (1732314211322), we get a palindrome (3963438343693).
The spelling of 2231124132371 in words is "two trillion, two hundred thirty-one billion, one hundred twenty-four million, one hundred thirty-two thousand, three hundred seventy-one".
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