Base | Representation |
---|---|
bin | 10100110001111010… |
… | …000001101101100111 |
3 | 2010120222012201022012 |
4 | 110301322001231213 |
5 | 331143401201211 |
6 | 14130002224435 |
7 | 1416625662602 |
oct | 246172015547 |
9 | 63528181265 |
10 | 22312131431 |
11 | 950a686647 |
12 | 43a835511b |
13 | 2147709845 |
14 | 11193d1339 |
15 | 8a8c36d8b |
hex | 531e81b67 |
22312131431 has 2 divisors, whose sum is σ = 22312131432. Its totient is φ = 22312131430.
The previous prime is 22312131427. The next prime is 22312131503. The reversal of 22312131431 is 13413121322.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22312131431 - 22 = 22312131427 is a prime.
It is a super-3 number, since 3×223121314313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 22312131397 and 22312131406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22312131931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11156065715 + 11156065716.
It is an arithmetic number, because the mean of its divisors is an integer number (11156065716).
Almost surely, 222312131431 is an apocalyptic number.
22312131431 is a deficient number, since it is larger than the sum of its proper divisors (1).
22312131431 is an equidigital number, since it uses as much as digits as its factorization.
22312131431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864, while the sum is 23.
Adding to 22312131431 its reverse (13413121322), we get a palindrome (35725252753).
The spelling of 22312131431 in words is "twenty-two billion, three hundred twelve million, one hundred thirty-one thousand, four hundred thirty-one".
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