Base | Representation |
---|---|
bin | 10100110001111010… |
… | …000100101001001001 |
3 | 2010120222020022202201 |
4 | 110301322010221021 |
5 | 331143402042213 |
6 | 14130002400201 |
7 | 1416626042566 |
oct | 246172045111 |
9 | 63528208681 |
10 | 22312143433 |
11 | 950a694668 |
12 | 43a8360061 |
13 | 2147712148 |
14 | 11193d586d |
15 | 8a8c3a6dd |
hex | 531e84a49 |
22312143433 has 2 divisors, whose sum is σ = 22312143434. Its totient is φ = 22312143432.
The previous prime is 22312143401. The next prime is 22312143443. The reversal of 22312143433 is 33434121322.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20908292409 + 1403851024 = 144597^2 + 37468^2 .
It is a cyclic number.
It is not a de Polignac number, because 22312143433 - 25 = 22312143401 is a prime.
It is a super-3 number, since 3×223121434333 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (22312143443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11156071716 + 11156071717.
It is an arithmetic number, because the mean of its divisors is an integer number (11156071717).
Almost surely, 222312143433 is an apocalyptic number.
It is an amenable number.
22312143433 is a deficient number, since it is larger than the sum of its proper divisors (1).
22312143433 is an equidigital number, since it uses as much as digits as its factorization.
22312143433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 28.
Adding to 22312143433 its reverse (33434121322), we get a palindrome (55746264755).
The spelling of 22312143433 in words is "twenty-two billion, three hundred twelve million, one hundred forty-three thousand, four hundred thirty-three".
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