Base | Representation |
---|---|
bin | 1010001001011001011010… |
… | …01000000110100001000111 |
3 | 2221000010001011011020001122 |
4 | 11010230231020012201013 |
5 | 10411034223210420122 |
6 | 115242300252144155 |
7 | 4462032502230365 |
oct | 504545510064107 |
9 | 87003034136048 |
10 | 22313112201287 |
11 | 7122a35155006 |
12 | 260452016805b |
13 | c5b16b07199b |
14 | 571d63464635 |
15 | 28a636739142 |
hex | 144b2d206847 |
22313112201287 has 2 divisors, whose sum is σ = 22313112201288. Its totient is φ = 22313112201286.
The previous prime is 22313112201227. The next prime is 22313112201313. The reversal of 22313112201287 is 78210221131322.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22313112201287 - 210 = 22313112200263 is a prime.
It is a super-3 number, since 3×223131122012873 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22313112201227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11156556100643 + 11156556100644.
It is an arithmetic number, because the mean of its divisors is an integer number (11156556100644).
Almost surely, 222313112201287 is an apocalyptic number.
22313112201287 is a deficient number, since it is larger than the sum of its proper divisors (1).
22313112201287 is an equidigital number, since it uses as much as digits as its factorization.
22313112201287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 22313112201287 in words is "twenty-two trillion, three hundred thirteen billion, one hundred twelve million, two hundred one thousand, two hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •