223143115120493 has 2 divisors, whose sum is σ = 223143115120494. Its totient is φ = 223143115120492.

The previous prime is 223143115120487. The next prime is 223143115120561. The reversal of 223143115120493 is 394021511341322.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 156485638774084 + 66657476346409 = 12509422^2 + 8164403^2 .

It is a cyclic number.

It is not a de Polignac number, because 223143115120493 - 2¹⁰ = 223143115119469 is a prime.

It is a super-3 number, since 3×223143115120493³ (a number of 44 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 223143115120493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (223143115120433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111571557560246 + 111571557560247.

It is an arithmetic number, because the mean of its divisors is an integer number (111571557560247).

Almost surely, 2^{223143115120493} is an apocalyptic number.

It is an amenable number.

223143115120493 is a deficient number, since it is larger than the sum of its proper divisors (1).

223143115120493 is an equidigital number, since it uses as much as digits as its factorization.

223143115120493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 223143115120493 in words is "two hundred twenty-three trillion, one hundred forty-three billion, one hundred fifteen million, one hundred twenty thousand, four hundred ninety-three".