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2231817350093 is a prime number
BaseRepresentation
bin100000011110100010101…
…011100010101111001101
321220100201012002101111022
4200132202223202233031
5243031230220200333
64425141023203525
7320146341316502
oct40364253425715
97810635071438
102231817350093
11790565790041
1230065b1465a5
131325c8601906
147a0404cb4a9
153d0c48aec98
hex207a2ae2bcd

2231817350093 has 2 divisors, whose sum is σ = 2231817350094. Its totient is φ = 2231817350092.

The previous prime is 2231817350041. The next prime is 2231817350123. The reversal of 2231817350093 is 3900537181322.

2231817350093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1469763426244 + 762053923849 = 1212338^2 + 872957^2 .

It is a cyclic number.

It is not a de Polignac number, because 2231817350093 - 212 = 2231817345997 is a prime.

It is a super-3 number, since 3×22318173500933 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2231817350293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1115908675046 + 1115908675047.

It is an arithmetic number, because the mean of its divisors is an integer number (1115908675047).

Almost surely, 22231817350093 is an apocalyptic number.

It is an amenable number.

2231817350093 is a deficient number, since it is larger than the sum of its proper divisors (1).

2231817350093 is an equidigital number, since it uses as much as digits as its factorization.

2231817350093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 272160, while the sum is 44.

The spelling of 2231817350093 in words is "two trillion, two hundred thirty-one billion, eight hundred seventeen million, three hundred fifty thousand, ninety-three".