Base | Representation |
---|---|
bin | 1010001001100110011111… |
… | …00110010100101110100111 |
3 | 2221000210011110000202110102 |
4 | 11010303033212110232213 |
5 | 10411143113022000403 |
6 | 115245421052214315 |
7 | 4462401463103531 |
oct | 504631746245647 |
9 | 87023143022412 |
10 | 22320133000103 |
11 | 7125a08215084 |
12 | 260595b46a39b |
13 | c5ba1977a803 |
14 | 57242ba76851 |
15 | 28a8e7cb0b88 |
hex | 144ccf994ba7 |
22320133000103 has 2 divisors, whose sum is σ = 22320133000104. Its totient is φ = 22320133000102.
The previous prime is 22320133000097. The next prime is 22320133000127. The reversal of 22320133000103 is 30100033102322.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22320133000103 is a prime.
It is a super-3 number, since 3×223201330001033 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22320133000003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11160066500051 + 11160066500052.
It is an arithmetic number, because the mean of its divisors is an integer number (11160066500052).
Almost surely, 222320133000103 is an apocalyptic number.
22320133000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
22320133000103 is an equidigital number, since it uses as much as digits as its factorization.
22320133000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 22320133000103 its reverse (30100033102322), we get a palindrome (52420166102425).
The spelling of 22320133000103 in words is "twenty-two trillion, three hundred twenty billion, one hundred thirty-three million, one hundred three", and thus it is an aban number.
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